You are a Guest | Sign In Register as: Student Plus Student
Add to Scribble Pad

metal electrolysis

Asked by markr | Mar 17, 2003 | University Level > Chemistry > Coursework
markr asks:

electrolysis of a molten metal chloride MCl3 using a current of 6.50 A for 1397 seconds deposits 1.41 g of the metal at the cathode. What is the metal?

etutor answers:
One Faraday of charge will move one mole of electrons.
One Faraday is 96500 coulombs.
One coulomb is one amp per second. So in this case we are using 6.5 x 1397 coulombs = 9080.5 C. That is equivalent to 0.094 mol. of electrons.
In MCl3 the metal must be M3+, so it needs 3 moles of electrons to fully discharge a mole of it. Or 1/3 mol from one mol of electrons.
0.094 mol electrons produces 1.41 g
so 1 mol electrons produces 15 g
15 g is 1/3 moles. One mol is 45 g.
The metal is scandium.

0 student responses

Login or Register to post a response.

Student Profile

Last online Sat Jul 6 2002 7:24 AM GMT
Member since Aug 8, 2005
Profile type:

Popular Tags

Sponsored Links